Hexagonal Shaft

[Joe And Penny Goss]

Hi Ron, Yes that is probibly the numbers. How did you do that <G> For me the
shape of the hex gives support and strength due to the triangle. If the ( I
do not know what to call it ) widest measurment faces the line of the force
applied.  > force going this way.
Jim let me know that you find out.

Joe Goss
imatunr@srvinet.com
www.mothergoosetools.com
----- Original Message ----- 
From: "Ron Nossaman" <RNossaman@cox.net>
To: "College and University Technicians" <caut@ptg.org>
Sent: Sunday, November 16, 2003 9:42 PM
Subject: Re: Hexagonal Shaft


> Jim, Joe, etc,
> I figured Joe meant something other than 3/32, but since it's been
> addressed... As a quick expedient, how about just calculating the moment
of
> inertia (I) for the various cross sections as an indication of their
> relative stiffness, and cross sectional area as an indication of weight?
>
> circle
> D 0.25
> I 0.0001914
> Area 0.0490875
> Area/I 256.45714
> I/Area 0.0038993
>
> hex flat
> D 0.2429
> I 0.0001915
> Area 0.0488523
> Area/I 255.16001
> I/Area 0.0039191
>
> hex edge
> D 0.2377
> I 0.0001915
> Area 0.0467831
> Area/I 244.24221
> I/Area 0.0040943
>
> square
> D 0.2189
> I 0.0001913
> Area 0.0479172
> Area/I 250.43194
> I/Area 0.0039931
>
> Ron N
>


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