Hi, I believe the problem is semantics. If you add a M6 and a p12 the result is a M17. What Richard is suggesting is that the M6 and the M17 beat at the same speed, as a "proof" of the p12. f2--d3 = M6 f2--a4 = M17 if M6 beats at same rate as M17, then d3--a4 = p12 As this is an "outside" test (f2 is not between d3 and a4) it doesn't matter if f2 is flat or sharp. At 08:43 PM 23/09/2004 +0100, you wrote: >Ok.. once more.... > >take any ol 12th... say D3 - A4. The major sixth below the lowest >note of this particular 12th is F2. These three notes share a >coincident at A4 (1)... i.e. the fundemental of A4. > >So.... to insure the D3(3) is just with A4(1)... i.e. a pure 12th.... >then the beat rates of both D3(3) and A4(1) against F2(5) will be the same. > >This works for any 12th... just take the major sixth below the lowest >note, play that with each note of the 12th and compare the beat >resultant rates. Ric, Regards, Don Rose, B.Mus., A.M.U.S., A.MUS., R.P.T. mailto:pianotuna@accesscomm.ca http://us.geocities.com/drpt1948/ 3004 Grant Rd. REGINA, SK S4S 5G7 306-352-3620 or 1-888-29t-uner
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