Loading the tuning pin

[William Monroe]

OK,

I'd take that explanation over mine.  So I guess I'll have to accept that 
I'm leaving pins twisted.  Might take some getting used to.  ;-]

Good explanation.

William R. Monroe

>
> I'd like to clear up a point of basic physics here. You're not leaving the 
> pin with no twist in it, you're ideally leaving it with whatever twist it 
> takes to counter the opposing twisting force from string tension. That's 
> the equilibrium you're after. You have no way to tell what twist is still 
> in the pin because you can't measure it directly. The only indications you 
> get are what you feel, and what you hear (or see on your ETD) as the 
> string pitch changes. When you leave the pin at a point where it takes the 
> same or very slightly more force on the tuning hammer to lower pitch X 
> amount that it does to raise pitch by X amount, you're in the ball park. 
> At that balance of forces, the pin will be left with some twist, but will 
> be in balance with string tension.
> Ron N
>
>