Found a typo in 4th sentence and changed it... ... "the change in tension" should have read "the change in frequency". It is corrected below. Cheers RicB Hi JD Since you havent responded to this I thought I would supply the answer you queried. This answer takes into consideration only the tension and frequency change brought about by the deflection change you sketch out below. It doesnt take into consideration that the strings offset angle through the bridge pins will also change by such a 0.5 mm sink into the bridge... and hence its length for this segment changes significantly altering the pitch and tension further and in the same direction. But...for the simple case of the deflection alone... the change in frequency (with a starting tension of 157 lbs and frequency of 2105 hz, lengths as per yours below) for a 0.5 mm drop in deflection is about 19 hz. The strings length will shorten by about 0,018752 mm which immediately lowers tension by roughly 2,8283 lbs. Using the formula F=SQRT((T*398*10^6)/(length in mm *string diameter in mm )^2) for frequency then... you get about 19 hz change. Works out the same using your formula for F and a value of 18036 for K. Quite a big difference from your 0.026 hz I'd say. You can actually measure this on a monochord if you like... very easy to construct something to do this I would think. If anyone wants a copy of the basic spreadsheet worked out to calculate this stuff using the formulas supplied by Galembo I'd be glad to share it with you and welcome comments. Cheers RicB
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