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<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">Hi-<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /><o:p></o:p></SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">Of course you can have acceptable DW's & UW's and at the same time have a wide range of moments of inertia, some which may be acceptable and some which may not be. Or the front weights could be too high.<SPAN style="mso-spacerun: yes"> </SPAN>That's why I don't think UW/DW alone tells us enough about how the action "feels". </SPAN><SPAN style="FONT-FAMILY: Arial"><FONT size=3> <o:p></o:p></FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-FAMILY: Arial"><o:p><FONT size=3> </FONT></o:p></SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">Here is a formula for moment of inertia</SPAN><SPAN style="FONT-FAMILY: Arial"><FONT size=3> (I):<o:p></o:p></FONT></SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><FONT size=3><SPAN style="FONT-FAMILY: Arial; mso-bidi-font-family: 'Times New Roman'"><SPAN style="mso-spacerun: yes"> </SPAN>I= m<SUB>1</SUB>r<SUB>1</SUB><SUP>2</SUP> + m<SUB>2</SUB>r<SUB>2</SUB><SUP>2</SUP> + m<SUB>3</SUB>r<SUB>3</SUB><SUP>2</SUP> + ... + m<SUB>n</SUB>r<SUB>n</SUB><SUP>2<SPAN style="mso-spacerun: yes"> </SPAN></SUP></SPAN><SPAN style="FONT-FAMILY: Arial"><o:p></o:p></SPAN></FONT></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"><o:p> </o:p></SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">Where m is the mass and r (radius) is the distance that the mass is from the balance hole of the key.<SPAN style="mso-spacerun: yes"> </SPAN>The key itself has some moment of inertia too.<o:p></o:p></SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"><o:p> </o:p></SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">So the action in question (Wim’s D) might weigh off acceptably (DW and UW), but also may have a too heavy a front weight, and/or moment of inertia.<o:p></o:p></SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"><o:p> </o:p></SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">Stanwood has come up with a good standard of front weights.<SPAN style="mso-spacerun: yes"> </SPAN>Moment of inertia standards are a little more ambiguous at this point. More importantly is that the moments be reasonably smooth from key to key.</SPAN></P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"></SPAN> </P>
<P class=MsoNormal style="MARGIN: 0in 0in 0pt"><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">Brian is right.</SPAN></P></DIV>
<DIV><B><I></I></B> </DIV>
<DIV><B><I>Brian Lawson <lawsonic@bdmail.co.za></I></B> wrote:</DIV>
<BLOCKQUOTE class=replbq style="PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #1010ff 2px solid">Hi, I think he is referring to the English language with use of a virgule and<BR>not a division sign<BR><BR>3 : a mark / used typically to denote "or" (as in and/or), "and or" (as in<BR>straggler/deserter), or "per" (as in feet/second) -- called also slash, solidus,<BR>virgule<BR><BR>Brian<BR><BR><BR><BR>----- Original Message -----<BR>From: "Richard Brekne" <RICHARD.BREKNE@GRIEG.UIB.NO><BR>To: "College and University Technicians" <CAUT@PTG.ORG><BR>Sent: Thursday, December 18, 2003 3:29 PM<BR>Subject: Re: Touch weight<BR><BR><BR><BR><BR>madelyn mrykalo wrote:<BR><BR>> HI-More telling than downweight/upweight is moment of inertia/front<BR>> weight (which are two different things). UW/DW will not, in and of<BR>> itself, tell much of anything about the action's feel.<BR>><BR><BR>I think you want to explain this a bit further for us. How exactly are<BR>you ariving at the
moment of inertia (for the key) and what does<BR>dividing that by FW tell us exactly ?<BR><BR>Cheers<BR>RicB<BR><BR></BLOCKQUOTE><BR><BR>Vince Mrykalo<br>University of Utah<p><hr SIZE=1>
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