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<DIV dir=ltr align=left><SPAN class=181133203-30042007><FONT face=Arial
color=#0000ff size=2>Mail me privately, off list, would you. It's a waste of
list time for my silly question. Thanks</FONT></SPAN></DIV>
<DIV dir=ltr align=left><SPAN class=181133203-30042007><FONT face=Arial
color=#0000ff size=2>les</FONT></SPAN></DIV><BR>
<DIV class=OutlookMessageHeader lang=en-us dir=ltr align=left>
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<FONT face=Tahoma size=2><B>From:</B> caut-bounces@ptg.org
[mailto:caut-bounces@ptg.org] <B>On Behalf Of </B>RicB<BR><B>Sent:</B> Sunday,
April 29, 2007 6:21 PM<BR><B>To:</B> caut@ptg.org<BR><B>Subject:</B> [CAUT] Wire
Stretch<BR></FONT><BR></DIV>
<DIV></DIV>Hi Les...<BR><BR>First let me say I understand your feelings here...
but if you get hooked on figuring out this stuff you probably will find you are
far brighter at math then you may think now. Secondly let me say that after
re-reading your post... this bit of math doesnt quite address what you were
asking for. This is about finding the change in string tension that occurs when
one deflects or changes the deflection of a string and doing nothing
else.<BR><BR>Delta is a greek word used in math for <<change
in>> Usually denoted by a triangle. Not a big thing really. So
the first bit below is simply <BR><BR><<the change in Tension>> =
Youngs Modulus * Cross Section of the string * << the change in the string
length because of the deflection >> divided by the origional length of the
string.<BR><BR>Not so tough really.. just some multiplication and
division.<BR><BR>The second bit is much of the same thing <BR><BR>Frequency =
the square root of (Tension divided by (the length of the string squared times
the diameter of the string squared times the strings density
constant)<BR><BR>You can use McFerrins book to find out a good deal about some
important formulas we use. A bit of head scratching and insistance on
digging out your high school pre-calc and algebra books will take you a long
ways. <BR><BR>I can send you a spread sheet that does all this if you
like...<BR><BR>Cheers<BR>RicB<BR>
<BLOCKQUOTE><BR>Uh, there's a reason I did poorly in math........... But
I know some folks<BR>who can tear this apart step by step.... thanks<BR>lse
<BR><BR><BR><BR>
<BLOCKQUOTE>I just posted a link to a such an approach. In the end its
quite easy. <BR>You first find the change in tension a give change in
deflection yields, and<BR>then you have all you need to use standard
frequency formulas.<BR><BR> Delta T = ES (Delta L / L). <BR><BR>Then
calculate for the new frequency with your known wire diameter,
speaking<BR>length and tension and the so called K constant... which in this
case is<BR><BR> (Pi * string density / 981)<BR><BR>f =
Sqrt(T/(L^2*d^2 *K)<BR><BR>Ok ?<BR><BR>Cheers<BR>RicB<BR><BR>Is there some
source or "relatively easy" formula for calculating how much a<BR>string
must move through a termination point to produce pitch
change? I'd<BR>like to have some tiny bit of basic
information so that in describing pitch<BR>corrections of significant
distance I can use the information to explain the<BR>likelihood that the
piano will need a retuning in the near future.<BR>thanks<BR>les
bartlett<BR></BLOCKQUOTE><BR>No virus found in this incoming
message.<BR>Checked by AVG Free Edition. <BR>Version: 7.5.467 / Virus
Database: 269.6.2/779 - Release Date: 04/28/2007<BR>3:32 PM<BR> <BR>
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<P><FONT size=2>No virus found in this incoming message.<BR>Checked by AVG Free
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