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<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'>See my other post but of course diameter
plays a role. It is a factor in determining break point percentage.
A thicker string will have a higher break point percentage and a thicker string
will need to be at a higher tension to achieve a certain frequency at a given
length than will a thinner string. Simple stuff. The claim about
BPP as a factor in determining which string will go out of tune more goes way
back. You don’t need to use BPP in the formula, you can simply
calculate it for the two strings in question and observe the relationship—see
my other (corrected post). Please don’t be so antagonistic. I’m
really trying to help you here. </span></font></p>
<p class=MsoNormal><font size=2 color=navy face=Arial><span style='font-size:
10.0pt;font-family:Arial;color:navy'> </span></font></p>
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<p><font size=2 color=navy face="Times New Roman"><span style='font-size:10.0pt;
color:navy'>David Love<br>
davidlovepianos@comcast.net<br>
www.davidlovepianos.com</span></font><font color=navy><span style='color:navy'>
</span></font></p>
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<p class=MsoNormal style='margin-left:.5in'><font size=2 color=black
face=Tahoma><span style='font-size:10.0pt;font-family:Tahoma;color:windowtext'>-----Original
Message-----<br>
<b><span style='font-weight:bold'>From:</span></b> caut-bounces@ptg.org
[mailto:caut-bounces@ptg.org] <b><span style='font-weight:bold'>On Behalf Of </span></b>Richard
Brekne<br>
<b><span style='font-weight:bold'>Sent:</span></b> Monday, June 11, 2007 2:57
AM<br>
<b><span style='font-weight:bold'>To:</span></b> caut@ptg.org<br>
<b><span style='font-weight:bold'>Subject:</span></b> [CAUT] pre-stretching new
string?</span></font></p>
<p class=MsoNormal style='margin-left:.5in'><font size=3 color=black
face="Times New Roman"><span style='font-size:12.0pt'> </span></font></p>
<p class=MsoNormal style='margin-left:.5in'><font size=3 color=black
face="Times New Roman"><span style='font-size:12.0pt'>David<br>
<br>
Below are your two posts on the matter. The lower post clearly states
your original claim... which I fail to see you have supported. In fact...
half of it is directly wrong as the example I gave showed. Diameter doesnt play
into it at all... tho it seems pretty clear you claim it does. As for the
rest...see subsequent posts.<br>
<br>
The upper quote suddenly jumps into a new claim about breaking point
percentages which is off in an entirely different tangent. Breaking
precentage is not part of any tension formula... it is a procedure of its own.
So this fits into a claim that you can (and I quote) <br>
<br>
"You can certainly rewrite the formula to isolate
pitch, or tension, or length, or diameter." <br>
<br>
er... how ?<br>
<br>
Perhaps you have a way of calculating change in pitch from change in length
with some breaking % formula now ? Please... if you have some formula the
rest of us do not... share it with us. I spent a couple months exchanging
posts with Mark Davidson, Sarah, Alexander Galembo, Jim Ellis, Rhodes, Askenfelt
and a couple others and each and every one of them reviewed Galembos paper to
me and agreed this was the basic approach and a quite adequate one as well of
calculating change of pitch for change in length. <br>
<br>
Cheers<br>
RicB</span></font></p>
<p class=MsoNormal style='margin-left:.5in'><font size=3 color=black
face="Times New Roman"><span style='font-size:12.0pt'><br>
Grin<br>
"You will find in the example you listed below that since both speaking<br>
lengths are equal, they will both yield equal break point percentages.<br>
While you have to increase the tension in the string with the greater<br>
diameter, it also has a higher break point so the break point percentage<br>
does not change. Set up your example using two notes different speaking<br>
lengths to begin with so that the BPPs are not equal. Then run your<br>
calculations for an equal change in length. " </span></font></p>
<p class=MsoNormal style='margin-left:.5in'><font size=3 color=black
face="Times New Roman"><span style='font-size:12.0pt'><br>
"Sorry, but it's not quite a complete enough formula for purposes of this<br>
discussion. When comparing two strings that produce the same pitch but
with<br>
different tensions, either the original length will be different or the<br>
diameter will be different (or both), thus a similar change in length will<br>
yield a different change in tension and thus pitch." </span></font></p>
<p class=MsoNormal style='margin-left:.5in'><font size=3 color=black
face="Times New Roman"><span style='font-size:12.0pt'><br>
</span></font></p>
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