<br><br> <div><span class="gmail_quote">On 11/1/07, <b class="gmail_sendername">Richard Brekne</b> <<a href="mailto:ricb@pianostemmer.no">ricb@pianostemmer.no</a>> wrote:</span> <blockquote class="gmail_quote" style="PADDING-LEFT: 1ex; MARGIN: 0px 0px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">  Either way moving<br>the whole whippen 2 mm moves both points 2 mm. </blockquote> <div> </div> <div> </div> <div>This is where I think you are missing it. The jack center to wippen center cannot change in distance. The RA remains the same length. 1 to 1.477 changes to 1 to 1.430  with a 2mm rail move on the S&S wippen I just measured. It can lift more weight. Not much but some. </div> <div> </div> <div>If you lean the post or the jack from the tangent line of the RA, you have to use vector analysis and angular momentum formulas to figure the output transfered to the jack. It is not a distance measurment factored back directly against the EA. As the jack leans it is an exponential function based on the number of degrees the jack rotates. In other words from 0* to 30* there is not much change in force then from 30 to 60* it decreases rapidily and from 60* to 90* force is about 0. </div> <div> </div> <div>As it is I have a lot more to think about and detail, thank you and I will get back as soon as I can.</div> <div> </div> <div>Keith</div> <div> </div><br> </div>