<HTML><FONT FACE=arial,helvetica><FONT SIZE=2 FAMILY="SANSSERIF" FACE=
="Arial" LANG="0">In a message dated 2/2/2003 8:37:36 PM Pacific Standar=
d Time, Erwinspiano writes:<BR>
<BR>
<BLOCKQUOTE TYPE=CITE style="BORDER-LEFT: #0000ff 2px solid; MARGIN-LEFT=
: 5px; MARGIN-RIGHT: 0px; PADDING-LEFT: 5px">Subj: <B>Re: Bearing difference=
on different soundboards </B><BR>
Date: 2/2/2003 8:37:36 PM Pacific Standard Time<BR>
From: <A HREF="mailto:Erwinspiano">Erwinspiano</A><BR>
To: <A HREF="mailto:oleg-i@wanadoo.fr">oleg-i@wanadoo.fr</A><BR>
<BR>
<BR>
<BR>
In a message dated 2/2/2003 3:50:34 PM Pacific Standard Time, oleg-i@wanadoo=
.fr writes:<BR>
<BR>
<BLOCKQUOTE TYPE=CITE style="BORDER-LEFT: #0000ff 2px solid; MARGIN-LEFT=
: 5px; MARGIN-RIGHT: 0px; PADDING-LEFT: 5px">Subj: <B>RE: Bearing difference=
on different soundboards </B><BR>
Date: 2/2/2003 3:50:34 PM Pacific Standard Time<BR>
From: <A HREF="mailto:oleg-i@wanadoo.fr">oleg-i@wanadoo.fr</A><BR>
To: <A HREF="mailto:Erwinspiano@aol.com">Erwinspiano@aol.com</A><BR>
<I>Sent from the Internet </I><BR>
<BR>
<BR>
<BR>
</FONT><FONT COLOR="#0000ff" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0">I understand that if we see,=
for instance 1/4 inch crown from below the board, that does not really mean=
that having 1/4 distance bearing at the string rest will absorb the whole c=
rown, it depends of the back string length vs. the speaking length.<BR>
</FONT><FONT COLOR="#000080" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0"><B><BR>
<BLOCKQUOTE TYPE=CITE style="BORDER-LEFT: #0000ff 2px solid; MARGIN-LEFT=
: 5px; MARGIN-RIGHT: 0px; PADDING-LEFT: 5px"></FONT><FONT COLOR="#000000"=
style="BACKGROUND-COLOR: #ffffff" SIZE=2 FAMILY="SANSSERIF" FACE="A=
rial" LANG="0"></B>Isaac--Even with 1/4 inch crown The board could actuall=
y be pushed down to flat under the situation you describe, if the board is r=
eally weak. With the strings off try pushing down on a board with your hands=
and watch how much it moves so that you can get a feel for how stiff it wil=
l be. If it has some strength it will have resistence that will =
not permit the 1/4 inch distance bearing to push it flat.</FONT><FONT COLOR=
="#0000ff" style="BACKGROUND-COLOR: #ffffff" SIZE=2 FAMILY="SANSSERI=
F" FACE="Arial" LANG="0"><BR>
</FONT><FONT COLOR="#000000" style="BACKGROUND-COLOR: #ffffff" SIZE=3=
FAMILY="SANSSERIF" FACE="Arial" LANG="0">.</FONT><FONT COLOR="#000=
000" style="BACKGROUND-COLOR: #ffffff" SIZE=2 FAMILY="SANSSERIF" FACE=
="Arial" LANG="0"><BR>
</FONT><FONT COLOR="#0000ff" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0">Dale, I mean :</FONT><FONT =
COLOR="#000000" style="BACKGROUND-COLOR: #ffffff" SIZE=2 FAMILY="SAN=
SSERIF" FACE="Arial" LANG="0"><BR>
<BR>
</FONT><FONT COLOR="#0000ff" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0">If you have 1/4' crown=
</FONT><FONT COLOR="#000000" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0"> </FONT><FONT COLOR="#000=
0ff" style="BACKGROUND-COLOR: #ffffff" SIZE=2 FAMILY="SANSSERIF" FACE=
="Arial" LANG="0">, and you have 1/4" height difference at the rear stri=
ng rest, even if the string became straight under tension, (defluxion absorb=
ed) the board will not deflect 1/4", but less, because the 1/4" 'leverage' i=
s divided by the string's length, anyway that was my idea and that make sens=
e.</BLOCKQUOTE><BR>
</BLOCKQUOTE></FONT><FONT COLOR="#000000" style="BACKGROUND-COLOR: #fff=
fff" SIZE=2 FAMILY="SANSSERIF" FACE="Arial" LANG="0"><BR>
</FONT><FONT COLOR="#0000ff" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0"><BR>
</FONT><FONT COLOR="#000000" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0"><BR>
<B> >>If the string actually became straight the board would be flat&n=
bsp; but if the board has resistence it won't allow the string to become com=
pletly flat. Does that make sense. The problem is old CC boards most often d=
o not have much resistence or crown.</B><BR>
<BR>
<BLOCKQUOTE TYPE=CITE style="BORDER-LEFT: #0000ff 2px solid; MARGIN-LEFT=
: 5px; MARGIN-RIGHT: 0px; PADDING-LEFT: 5px"><BLOCKQUOTE TYPE=CITE style=
="BORDER-LEFT: #0000ff 2px solid; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px; PAD=
DING-LEFT: 5px"></FONT><FONT COLOR="#0000ff" style="BACKGROUND-COLOR: #=
ffffff" SIZE=2 FAMILY="SANSSERIF" FACE="Arial" LANG="0">So the stati=
c method explained by Nick Gravagne is OK, showing how to compute a maximum =
amount of down bearing , or distance bearing, in regard of the existing crow=
n (taken rib by rib) and still having some security in regard of the possibl=
e collapse of the board.</BLOCKQUOTE><BR>
</BLOCKQUOTE></FONT><FONT COLOR="#000000" style="BACKGROUND-COLOR: #fff=
fff" SIZE=2 FAMILY="SANSSERIF" FACE="Arial" LANG="0"><BR>
</FONT><FONT COLOR="#0000ff" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0"><BR>
</FONT><FONT COLOR="#000080" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0"><B><BR>
>> Once again No it doesn't work exactly. His method takes=
the rear string length and multiplies by .026. For example 4 inches t=
imes .026 equals .104 distance bearing. This gives a 1 &1/2 degree=
angle of deflection on a 60ft crowned board. And These figures only work on=
a new fully crowned board. <BR>
Now here is the part I'm having trouble making clear to y=
ou. First I've done it his way and it doesn't work. He himself has modified =
his procedure but hasn't revised the article. What will happen if you do it =
as Nick has written is that as the tenor is strung first the board is =
compressing so that when you reach the beginning of the first capo section t=
he nice distance bearing you thought you had calculated is disappeared as th=
e sounbboard sunk under load . You can check it with a bearing string. So pr=
e stressing compensates for this. Read the article I suggested you'll be enl=
ightened.<BR>
Pre-stressing makes so much sense you'll be amazed<BR>
regards Dale<BR>
</FONT><FONT COLOR="#000000" style="BACKGROUND-COLOR: #ffffff" SIZE=2=
FAMILY="SANSSERIF" FACE="Arial" LANG="0"></B><BR>
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