<HTML>In a message dated 9/11/03 11:26:18 AM Central Dayligh= t Time, marysmith@mail.utexas.edu writes: <BLOCKQUOTE TYPE=CITE style="BORDER-LEFT: #0000ff 2px solid; MARGIN-LEFT= : 5px; MARGIN-RIGHT: 0px; PADDING-LEFT: 5px">SO even if you lower the tray,the flanges might still need to be at 1-1/2" to get <B= R> proper lift. But, as Fred and Eric have correctly pointed out, you really <B= R> need to break down and replace the back action, and convert that rascal pitman. If you're not ready to replace the back action, for budget or time <= BR> reasons, then replace the key end felt again, see if you can wiggle the underlever height a bit, and convert the pitman anyway. </BLOCKQUOTE> Let me see if I can understand this.  I realize the angle of the lever,= as Fred sais, is "the angle of the levers as the manner in which the two ar= cs intercept - arcs of underlever versus arc of key". That is why the lever = is digging into the lifter felt. That is why I want to lower the tray, to re= duce that angle, and at the same time lower the height of the lever to 1 1/2= ".  But isn't the pitman the block of wood into which the tray is attached by th= e pin? So if I lower the pivot point, I will lower the tray. The question I = have is, how much should I lower the pivot point to lower the height of the = lever an 1/8"? And I should, I presume, cut off the block and redrill the sc= rew holes, right? Wim </HTML>