Don, You're right about the square of the distance. But it's also decreasing by the decreased mass, which we cut in half to maintain the same balance as we moved the weight away from the pivot. I=R*M^2. With 2oz at 1 inch, I=2. With 1oz at 2 inches, I = 4. Twice as much. Mike ----- Original Message ----- From: Don <drose@dlcwest.com> To: <pianotech@ptg.org> Sent: Thursday, March 29, 2001 12:24 PM Subject: Re: Ideal leading pattern: > Hi Mike, > > I was under the impression that the moment of inertia rose by the "square" > of the distance from the pivot point. I.E. 2 oz 1 inch from pivot would > give a value 1/4 of 1 oz 2 inches from pivot point. I may of course be out > to lunch on this (Big Mac attack?) > > At 11:47 AM 03/29/2001 -0600, you wrote: > >Paul, > > > >I believe you are mistaken regarding the inertia. Half the weight, twice > as far out, same > >static downweight, but twice the inertia. > > Regards, > Don Rose, B.Mus., A.M.U.S., A.MUS., R.M.T., R.P.T. > > Tuner for the Saskatchewan Centre of the Arts > > mailto:drose@dlcwest.com > http://donrose.xoasis.com/ > > 3004 Grant Rd. > REGINA, SK > S4S 5G7 > 306-352-3620 or 1-888-29t-uner > >
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