Ideal leading pattern:

[Mike and Jane Spalding]

Don,

(sheepishly)  yes, I=M*R^2

Mike

----- Original Message -----
From: Richard Brekne <Richard.Brekne@grieg.uib.no>
To: <pianotech@ptg.org>
Sent: Friday, March 30, 2001 8:54 AM
Subject: Re: Ideal leading pattern:


>
>
> Mike and Jane Spalding wrote:
>
> > Don,
> >
> > You're right about the square of the distance.  But it's also decreasing
by
> > the decreased mass, which we cut in half to maintain the same balance as
we
> > moved the weight away from the pivot.  I=R*M^2.   With 2oz at 1 inch,
I=2.
> > With 1oz at 2 inches, I = 4.    Twice as much.
> >
> > Mike
> >
>
> grin...er not to be picky... but didnt you mean to write I=M*R^2 since we
are
> talking the square of the distance and not of the mass ??
>
> --
> Richard Brekne
> RPT, N.P.T.F.
> Bergen, Norway
> mailto:Richard.Brekne@grieg.uib.no
>
>
>