Tuning pin size?

[Ron Nossaman]

>If "equivalent means essentially the same OK..if however "equivalent" means 
>the same then..... Nope don't work. :-)
> 2/0 pin circumference is .88548 and 4/0 is .91374.. a difference of 
>.03816....not much difference but there it is................in order to make 
>the same pitch change using a 2/0 pin as made with a 4/0 pin the 2/0 pin will 
>have to move 1.0319 farther than the 4/0.
>(check my math, and reasoning, though!:-)
> I agree that wear from tuning plays very little part in pinblock failure.
>Jim Bryant (FL)

No, that's not my point. I'm not talking about how many degrees the pin
must be moved to change the string pitch XXX frequency. I'm talking about
how far the surface of the pin must move relative to the surface of the
block. That's what determines wear isn't it? Since the string is tangent to
the pin, if you rotate the pin 0.005" in the block to affect a given pitch
change, that 0.005" could be on the surface of a 1/0, 6/0, or whatever, and
the movement and wear would be equivalent - not similar. The 1/0 would have
to rotate a greater number of degrees than the 6/0, to move the same
amount, but the ratio of pin surface movement in the block to string taken
up would be equivalent with any pin size - as would be the block wear if
the block's PSI friction load on the pin surface was the same in all cases.  

Whew. This is hard to explain for such a simple idea. If I could wave my
arms around and draw pictures, it would be easier.
 
Ron N