pin comparisons

[A440A@AOL.COM]

Greetings, 
   I have just finished Paul's article this month in the journal.  
Interesting views can be found on all aspects of tuning pins, since we all 
spend so much time with them,  and I am wondering what the numbers can tell 
me. Specifically, the difference in tuning control between sizes of pins.  I 
don't think that the increased radius of the larger pin is a significant 
factor.   I find (admittedly, I am NO math whiz, so if I have missed a step, 
please disregard everything that follows), that by determining the 
circumferance of two different sizes of pins, and then relating that to 
degrees of movement, the differences begin to seem academic. 
    Here is how it looks to me: 

   A pin that is .272" in diameter has a cir. of .85408".  This equates to 
.00237" per degree of rotation.  A .286" pin, by the same calculation has 
.0025" per degree of rotation. This means that the larger pin will move the 
string approx.  .0001" more per degree of rotation.  If we consistantly move 
pins by increments of 6 degrees in fine tuning, then the difference in pin 
size accounts for maybe .0006" (that is 6 ten-thousandths!!) difference in 
string length being pulled around the pin.   ( I have omitted the 1/2 string 
diameter from the circumferance equations,since that is a variable on a per 
string basis, though increasing the diameters of the two calculations would 
further reduce the percentage difference between them). 
   Since difference as it relates to tuning is based on changing the tension 
per degree of rotation, and tension/pitch relationships are functions of the 
square,  I have to ask just how much difference can be found from  .0006" of 
string movement, at the pin?  I don't think it would be a discernable 
quantity. Others?
Regards, 
Ed Foote RPT