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To elaborate -- since it is nearly always possible to place the bridge =
load relatively close to the center of the ribs I've simplified my =
process and simply use the relationship for a center-loaded beam of the =
shape that I use. (The exception being the relatively high treble and =
what the ribs are doing up there doesn't matter all that much anyway.)
Del
----- Original Message -----=20
From: Richard Brekne=20
To: Pianotech=20
Sent: October 02, 2003 12:31 PM
Subject: Re: RC vs CC again
=20
Just one more question on this.... how do you figure P when the load =
is not at the center ?...=20
I don't.=20
Del
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