>>Perhaps if we take the batter out of the picture my point will be more clear. Rigidly attach the bat to a fixture. Now throw the ball at it. If the object is to get max transfer of energy from ball to bat, then you want the least amount of ball rebound (the greater the rebound, the more the ball's energy stayed in the ball). What point on the bat will give the greatest ball rebound? Will it be the center of percussion? If so, then that doesn't seem like the spot that's giving greatest energy transfer from ball to bat. Hi Phil If the bat is mounted rigidly, then it doesn't matter where the ball hits it. Any point on the bat will give equal rebound. I think the problem here is one of perception: you seem to be primarily considering the effects of the speeding ball coming to the bat. But we have two things to consider: the energy the ball adds and the energy the bat adds. For the energy the ball adds, you are quite right: it doesn't matter where on the bat it hits. Every spot will give the same rebound. But for the energy the bat adds, the ball needs to hit at the spot where the greatest force from the bat will transfer. There is only a limited amount of energy, and if some goes into your hands (the reaction force), that takes away from what is available to the ball. The center of percussion is the spot where all of the energy of the rotating mass is focused. In our situation the strings are not speeding towards the hammer assembly. A better baseball analogy for us might be T Ball: the ball is stationary and the bat is the only thing in motion. Does that help you see why the center of percussion is the best place to hit it? I've appreciated your observations and questions. They motivated me to do a little more research. It would be interesting to do some testing by adding a little mass past the hammer to try to bring the CP right to the hammer. My calculations in the other post used the 11 gm bass hammer, which gave a cp pretty close to the hammer. Obviously, in the light treble hammers the Moment of Inertia of the shank assy will play a more significant role, which will move the CP closer to the pivot. Bill Spurlock recommends in his hammer hanging pamphlet to thin the treble shanks to remove mass, saying that will eliminate some of the "woody" sound that the you get in the extreme treble. I wonder if the woody sound is a result of the cp moving away from the hammer closer to the pivot. The resulting higher reaction force could be vibrating the shank assembly generating the noise. Thinning the shanks would move the cp back closer to the hammer. Somebody needs to do some experimenting with adding weight past the hammer. I realize now the number I came up with for the cp is the same as the answer you got, but I was confused (I get that way easily) as you didn't tell us anything about how to get the moment of inertia. So I incorrectly assumed you didn't use it. Mea culpa. Blessings, Dean Dean May cell 812.239.3359 PianoRebuilders.com 812.235.5272 Terre Haute IN 47802
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