Hi Steve. My reply is below... sorry about the length. Ric, I'm curious how you got these numbers. Seems backwards to me. Please help me understand how an effective speaking length change of 0.003 mm would require that much deflection of the bridge pin. Thanks, Steve Fujan Ric Brekne <ricbrek at broadpark.no> wrote: "To get a rougly 4 beat per second false beat this string needs to change in length by around 0.003 mm. That would require the pin to deflect nearly 1 mm !! " First look at it from an intuitive perspective. The string is <<anchored>> for all practical purposes in this context at the front termination. If you loosen the string grasping it exactly at the point it contacts the front bridge pin and move it left or right then it will follow an arc yes ?? no length difference at all there yes ? Ok.. so to get an increase in speaking length the path of the string moving in any sideways motion has to be outside that arc to get a change in distance. How much increase in length of this string do you imagine will occur with a 0.1 mm sideways movement from the pin ? Not much... not much at all. For simplicities sake and in keeping with the wobbly pin theory.... lets say the pins path of movement is the normal to the strings path. ie. 90 degrees. You have then a simple triangle to solve for. The first length is going to be the long leg, and the second the hypotenuse. Figure the short leg which will be the distance the pin would have to give sideways to allow for the change in length. If then... a string is 100 mm at rest, and when excited pin wobble allows it to achieve a 0.1 mm increase in length for the horizontal component... the effectively you have 100.1^2 - 100^2 = (Pin deflection)^2. The old a^2 + b^2 = c^2. Here the deflection distance is a, the length of the string at rest is b and the increased length is c. Solving for a you have a^2 = c^2 - b^2. In this example, the needed sideways deflection to get that 0.1 mm increase is 4.47 mm ! There is just no way the sideways pin wobble can possibly effect a large enough change in string length to cause any significant false beat. Its important to remember that any string deflection that actually does occur will spread this tension out over the entire length of the string.. not just the speaking length. This in effect reduces the net change. On the other hand... the idea that the pin terminates the vertical component and a regressed notch of about 0.1 mm terminating the horizontal component makes a whole lot more sense. You have two distinct lengths that fit the bill, and you dont need a bridge pin to be for all practical purposes in two places at the same time, let alone achieve distances that are impossible. Tho, as I said in my reply to Frank I would still like to know why there are so many exceptions to the rule. You could argue that it would be more accurate to figure the change in string length by using the two bridge pins and the front termination as the triangle to figure since any sideways movement in the front pin also lowers tension on the bridge face string segment. I didnt here to make my reply as simple as I can. Doing even with large angles between the two pins still doesnt get you anywhere near the amount of needed sideways deflection from the front bridge pin to account for any hearable beat. Cheers RicB
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