OK, I'd take that explanation over mine. So I guess I'll have to accept that I'm leaving pins twisted. Might take some getting used to. ;-] Good explanation. William R. Monroe > > I'd like to clear up a point of basic physics here. You're not leaving the > pin with no twist in it, you're ideally leaving it with whatever twist it > takes to counter the opposing twisting force from string tension. That's > the equilibrium you're after. You have no way to tell what twist is still > in the pin because you can't measure it directly. The only indications you > get are what you feel, and what you hear (or see on your ETD) as the > string pitch changes. When you leave the pin at a point where it takes the > same or very slightly more force on the tuning hammer to lower pitch X > amount that it does to raise pitch by X amount, you're in the ball park. > At that balance of forces, the pin will be left with some twist, but will > be in balance with string tension. > Ron N > >
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