Hi Mike !
THIS was the clue I needed... Yes I understand the roller capstan then
would move closer to the whippen center if it started below the magic
line, then get farther away as it passes. Now I just have to think a bit
on how the whippen heel is moving through this. Any given point on the
heel is not going to change distance from the whippen center through the
key stroke. So as the key raises towards the magic line, the roller
capstan would roll towards the whippen center as its distance from the
center decreased. Then at the magic line it would cease rolling and be
as close to the whippen center as possible, continuing upwards it would
reverse direction and begin to roll the opposite direction... away from
the whippen center... Almost like a pendulum motion if the starting
point was just as below the magic line as the ending point is above.
So..... how does an angled capstan that does'nt roll at all counter this
tendency... I can see I am going to have to re-read these posts and do
some thinking on it :)
Sorry bout the misquote... I'm sure Dale is ok with it.
Cheers and Thanks
RicB
Ric,
I wish I had reasoned out the quote you attribute to me - but it
belongs to Dale Erwin. I hope he won't mind if I attempt to answer
your question. Whether it ends up closer or further away depends
on where, in relation to the magic line, the motion occurs. For
example, if you start below the magic line and end an equal distance
above it, the roller will move towards the wippen center until you
reach the magic line, then move away, ending up right where it
started. The "best a tilted capstain could achieve" would depend on
how wide the capstain is.
Mike
Richard Brekne wrote:
Been trying to visualize this a bit and have the following to
ask you all about.
Consider a capstan that was a brass roller instead of what we
have today. So that as the key move and the capstan raises the
whippen this brass roller simply rolls along the underside of
the heal. Wouldn't this result in the roller-capstan starting
off further back on the heal (closer to the whippen flange)
then it ends up ? I.e. the opposite of this increasing leverage
concept ? And if that is the case.... then wouldn't it be more
likely that the best a tilted standard capstan could achieve is
to more or less compensate for that ?
Cheers
RicB
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