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<BODY style="BORDER-TOP-STYLE: none; BORDER-RIGHT-STYLE: none; BORDER-LEFT-STYLE: none; BORDER-BOTTOM-STYLE: none" text=#000000 bgColor=#ffffff>Dudess...<BR><BR>You can think through this doppler equation and can't figure out how to turn front rail pins...? ;-]<BR><BR>David Ilvedson, RPT<BR>Pacifica, California<BR><BR><BR><BR>
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Original message<BR>From: "Amy Zilk" <AMY@ZILKNET.NET><BR>To: "Pianotech List" <PIANOTECH@PTG.ORG><BR>Received: 6/22/2006 8:47:22 AM<BR>Subject: Re: Doppler puzzle<BR><BR>
<P align=left>Dude! What Doppler equation are you using? Both the original sent frequency and the observed frequency are in the equation. Manipulate the algebra to get the ratio, and the dimensions drop out.<BR></P>
<DIV class=moz-signature><BR>az<BR></DIV><BR><BR>John Delmore wrote:
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<P class=MsoNormal><FONT face=Arial color=navy size=2><SPAN style="FONT-SIZE: 10pt; COLOR: navy; FONT-FAMILY: Arial">No dice, Amy, you can’t use this dimensionless ratio in the Doppler equation. <SPAN> </SPAN>You have to have a frequency.<SPAN> </SPAN>It DOESN’T matter what pitch (frequency) you measure. <SPAN> </SPAN>The problem comes when you try to use a logarithmic scale (cents) in a linear equation (Hz in Doppler).<O:P></O:P></SPAN></FONT></P>
<P class=MsoNormal><FONT face=Arial color=navy size=2><SPAN style="FONT-SIZE: 10pt; COLOR: navy; FONT-FAMILY: Arial">JD<O:P></O:P></SPAN></FONT></P>
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<P class=MsoNormal><B><FONT face=Tahoma color=black size=2><SPAN style="FONT-WEIGHT: bold; FONT-SIZE: 10pt; COLOR: windowtext; FONT-FAMILY: Tahoma">From:</SPAN></FONT></B><FONT face=Tahoma color=black size=2><SPAN style="FONT-SIZE: 10pt; COLOR: windowtext; FONT-FAMILY: Tahoma"> <A class=moz-txt-link-abbreviated href="mailto:pianotech-bounces@ptg.org">pianotech-bounces@ptg.org</A> [<A class=moz-txt-link-freetext href="mailto:pianotech-bounces@ptg.org">mailto:pianotech-bounces@ptg.org</A>] <B><SPAN style="FONT-WEIGHT: bold">On Behalf Of </SPAN></B>Amy Zilk<BR><B><SPAN style="FONT-WEIGHT: bold">Sent:</SPAN></B> Wednesday, June 21, 2006 5:46 PM<BR><B><SPAN style="FONT-WEIGHT: bold">To:</SPAN></B> <?XML:NAMESPACE PREFIX = ST1 /><ST1:PERSONNAME w:st="on">Pianotech List</ST1:PERSONNAME><BR><B><SPAN style="FONT-WEIGHT: bold">Subject:</SPAN></B> Re: Doppler puzzle</SPAN></FONT><FONT color=black><SPAN style="COLOR: windowtext"><O:P></O:P></SPAN></FONT></P></DIV>
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<P class=MsoNormal><FONT face="Times New Roman" color=black size=3><SPAN style="FONT-SIZE: 12pt">Try dividing any two frequencies that differ by 10 cents. It's a constant. Ten cents difference anywhere in the spectrum is a constant frequency ratio of ~1.0579. The doppler shift is found in terms of this ratio and you can convert the 10 cents difference into the ratio of frequencies. It's counterintuitive for me (but not for Mark), that it doesn't matter which pitch you are measuring but that's the way it works.<BR>az<O:P></O:P></SPAN></FONT></P>
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