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<DIV>Greetings, </DIV>
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<DIV> (See below) This is so Greek to me! Where does one learn to calculate such things. Recommended reading would be appreciated!</DIV>
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<DIV>Thanks</DIV>
<DIV>Julia Gottshall</DIV>
<DIV>Reading, PA</DIV>
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<DIV>In a message dated 8/14/2006 8:32:21 PM Eastern Standard Time, sec@overspianos.com.au writes:</DIV>
<BLOCKQUOTE style="PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: blue 2px solid"><FONT face=Arial>Hi folks<BR>><BR>>I'm working on a spreadsheet for calculating a few different things <BR>>about downbearing and just wanted to check a few numbers with you <BR>>before going further then I am now.<BR>><BR>>Say you have the following string situation. Assume a bridge width of 0.<BR>><BR>>Speaking length 50mm<BR>>back length 25 mm<BR>>Angle at the bridge 178 degrees. (i.e. the angle created by the <BR>>strings deflection upwards.)<BR>>Tension on the string lengths 160 lbs<BR>><BR>>Are the following results then valid ?<BR>>Undeflected string length total 74,98984643<BR>>String angle from the front termination 1,333363422 degrees<BR>>String angle from the aliquot / hitchpin 0,666636578 degrees<BR>>String deflected Height 0,581737034 mm<BR>>Downwards force on the bridge. 5,584676 lbs<BR><BR>By 178 degrees I understand that you are talking about the angle <BR>underneath the string segments, ie. speaking length and back length <BR>segments. The downbearing force you have calculated is correct, since <BR>178 degrees if measured from underneath translates to a 2 deflection <BR>of the string over the bridge.<BR><BR>Sin 2 degrees*160 = 5,584676<BR><BR>Ron O.<BR>-- <BR>OVERS PIANOS - SYDNEY<BR> Grand Piano Manufacturers</FONT></BLOCKQUOTE></DIV>
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