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<DIV><FONT face=Arial size=2>Indeed. I examined Stanwood's formulas and see that
you are correct. Sorry for the misinformation.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Terry Farrell</FONT></DIV>
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<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV><FONT face=Arial size=2></FONT><BR></DIV>
<DIV class=Section1>
<P class=MsoNormal><FONT face=Arial color=navy size=2><SPAN
style="FONT-SIZE: 10pt; COLOR: navy; FONT-FAMILY: Arial">Actually, Stanwood’s
equation of balance won’t tell you that. The knuckle hanging is not
isolated in the formula. You have to sample and do a weigh off.
</SPAN></FONT></P>
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style="FONT-SIZE: 10pt; COLOR: navy; FONT-FAMILY: Arial"></SPAN></FONT> </P>
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<P><FONT face="Times New Roman" color=navy size=2><SPAN
style="FONT-SIZE: 10pt; COLOR: navy">David Love<BR></SPAN></FONT></P></DIV>
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style="FONT-SIZE: 10pt; FONT-FAMILY: Tahoma"></SPAN></FONT> </P>
<P class=MsoNormal style="MARGIN-LEFT: 0.5in"><FONT face=Tahoma size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: Tahoma">-----Original
Message-----<BR></SPAN></FONT><FONT face=Arial size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">Stanwood's equations of balance
would tell you that. Are you familiar with David Stanwood's
work?</SPAN></FONT></P>
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size=3><SPAN style="FONT-SIZE: 12pt"></SPAN></FONT> </P></DIV>
<DIV>
<P class=MsoNormal style="MARGIN-LEFT: 0.5in"><FONT face=Arial size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">Terry
Farrell</SPAN></FONT></P></DIV>
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<P class=MsoNormal style="MARGIN-LEFT: 0.5in"><FONT face=Arial size=2><SPAN
style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">----- Original Message -----
</SPAN></FONT></P></DIV>
<DIV style="font-color: black"><FONT face=Arial size=2><SPAN
style="FONT-SIZE: 12pt"></SPAN></FONT> </DIV>
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style="BORDER-RIGHT: medium none; PADDING-RIGHT: 0in; BORDER-TOP: medium none; MARGIN-TOP: 5pt; PADDING-LEFT: 4pt; MARGIN-BOTTOM: 5pt; PADDING-BOTTOM: 0in; MARGIN-LEFT: 3.75pt; BORDER-LEFT: #1010ff 1.5pt solid; PADDING-TOP: 0in; BORDER-BOTTOM: medium none">
<DIV>
<P class=MsoNormal style="MARGIN-LEFT: 0.5in"><FONT face="Times New Roman"
size=3><SPAN style="FONT-SIZE: 12pt">How do you figure out the change that
would occur in ACTION RATIO (AR) if everything remains constant (strike
weight, front weight,wippen balance weight, and balance weight) except the
knuckle is changed from 16.2 mm to 17mm, on paper, without actually trying
it out on the action?</SPAN></FONT></P></DIV></BLOCKQUOTE>
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style="MARGIN-BOTTOM: 12pt; MARGIN-LEFT: 0.5in; MARGIN-RIGHT: 0in"><FONT
face="Times New Roman" size=3><SPAN
style="FONT-SIZE: 12pt"></SPAN></FONT> </P>
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<P class=MsoNormal style="MARGIN-LEFT: 0.5in"><FONT face="Times New Roman"
size=3><SPAN style="FONT-SIZE: 12pt">Vince Mrykalo RPT
MPT</SPAN></FONT></P></DIV>
<DIV>
<P class=MsoNormal style="MARGIN-LEFT: 0.5in"><FONT face="Times New Roman"
color=red size=3><SPAN style="FONT-SIZE: 12pt; COLOR: red">University of
Utah</SPAN></FONT></P></DIV></DIV></DIV></DIV></BLOCKQUOTE></DIV></BLOCKQUOTE></BODY></HTML>