<font color='black' size='3' face='Times New Roman, Times, serif'>Rob sez: <br> <div style="font-family:helvetica,arial;font-size:10pt;color:black"> <div id="AOLMsgPart_1_dbdd3b85-8895-4417-b1cb-ddfa86dc4af0"> <div><br> </div> <div>I have a DeWalt 10amp 1/2" drill that'll go from 0-1200 rpm in a heartbeat. Fast would obviously be quicker. I just want to make sure there aren't any unforeseen pitfalls.  I figure my drill will pull each pin out in under 2 seconds. That's my preferred method.<font class="Apple-style-span" face="'Times New Roman', Times, serif">>></font></div> <div><font class="Apple-style-span" face="'Times New Roman', Times, serif"><br> </font></div> <div><font class="Apple-style-span" face="'Times New Roman', Times, serif">   I have always tried to figure just how much trigger I needed to apply to get the pin to stop spinning just as it came out of the hole.  With over 200 pins to remove, I don't want to waste 3 seconds per pin letting the drill stop, and I don't like to drop the spinning socket over the next pin, so, I want to let the pin almost stop the drill as it comes out the last thread or so.  I always get it just right about twenty holes from the finish line..</font></div> <div><font class="Apple-style-span" face="'Times New Roman', Times, serif">Regards, </font></div> <div><font class="Apple-style-span" face="'Times New Roman', Times, serif">Ed Foote RPT</font></div> <div> </div> </div>  </div> </font>