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<DIV><STRONG><FONT face=Arial size=3>I am having a problem figuring out, how a
swing test could even be done on a jack.</FONT></STRONG></DIV>
<DIV><STRONG><FONT face=Arial size=3>I have only done swing tests on hammer
flanges.</FONT></STRONG></DIV>
<DIV><STRONG><FONT face=Arial size=3>I use a gram guage for the other
flanges.</FONT></STRONG></DIV>
<DIV> </DIV>
<DIV><FONT face=Arial>John M. Ross<BR>Windsor, Nova Scotia, Canada<BR><A
href="mailto:jrpiano@win.eastlink.ca">jrpiano@win.eastlink.ca</A></FONT></DIV>
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style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B>
<A title=mcbeach@earthlink.net href="mailto:mcbeach@earthlink.net">Dave
Mckibben</A> </DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A title=pianotech@ptg.org
href="mailto:pianotech@ptg.org">pianotech</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Saturday, December 18, 2004 2:46
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> torque</DIV>
<DIV><BR></DIV>
<P>
<DIV align=center> </DIV>
<DIV>
<BLOCKQUOTE cite="" type="cite"><FONT face=Arial>Now I haven't tried this,
so I may well be speaking out of ignorance, but I have a reasonable concept
of how much flange friction there will be with 3-4 grams of resistance. A
jack weighs almost nothing. Seems to me if the jack needs to swing freely 7
full swing cycles, that would require almost no friction in the center.
Three to five grams friction in an action center with a shank and hammer
hanging from it will swing maybe three full cycles - and that has tons more
momentum. Seems like something may not be right here???</FONT></BLOCKQUOTE>
<BLOCKQUOTE cite="" type="cite"> </BLOCKQUOTE>
<BLOCKQUOTE cite="" type="cite"><FONT face=Arial>Terry
Farrell</FONT></BLOCKQUOTE>
<DIV><BR></DIV>
<DIV>I think there a couple of things askew here. One is that some
people are talking about hammer flange center pins and others are talking
about jack center pins. Two is that, with regard to center pin friction,
a gram reading by itself is meaningless. Action centers rotate, and that
rotation is caused by a torque, not a force. And the friction associated
with them is measured by a torque, not a force. A gram reading is a
measure of force. To get a torque you have to know the distance from the
center that the force is applied. On a hammer flange, 4 grams applied
next to the screw hole gives a completely different torque than 4 grams
applied at the tip of the flange. If you're going to specify a gram
reading for flange friction then you also need to define the point at which
you're taking that gram reading.</DIV>
<DIV><BR></DIV>
<DIV>Phil Ford</DIV>
<DIV>San Francisco, CA, USA, Earth</DIV></DIV>
<DIV> </DIV>
<DIV> </DIV>
<DIV>Yes..............Torque = force * distance</DIV>
<DIV>distance from pin where force is applied is part of the equation.</DIV>
<DIV> </DIV>
<DIV>Mckibben's</DIV>
<DIV><A href="mailto:mcbeach@earthlink.net">mcbeach@earthlink.net</A></DIV>
<DIV>surf sand and sea</DIV>
<DIV> </DIV>
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