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<DIV>----- Original Message ----- </DIV>
<DIV>
<DIV>From: "Ron Overs" <<A
href="mailto:sec@overspianos.com.au">sec@overspianos.com.au</A>></DI=
V>
<DIV>Subject: Re: Killer Octave Question</DIV></DIV>
<DIV><BR></DIV>
<DIV>SNIP</DIV>
<DIV> </DIV>
<DIV>> Sure the long bridge will rotate backwards <BR>> on its =
axis (from
end to end) just slightly to accommodate the crown <BR>> of the =
board, but it
will be so minimal as to be insignificant.</DIV>
<DIV><FONT face=Brisk></FONT> </DIV>
<DIV><FONT color=#800080>Please try and clarify the above statement. =
Are you
defining an axis going from the extreme treble end to the low tenor end =
of the
long bridge? Then are you speaking of the two ends rotating backwards to =
meet
the crowned board? I guess then one could speak of the killer octave =
area (or
thereabouts) rotating forward if the the two ends are considered as =
reference
points?</FONT></DIV>
<DIV><FONT face=Brisk></FONT> </DIV>
<DIV>> The <BR>> rib profile, 'stress in extreme fibre' =
and
paring profile is where <BR>> its at!</DIV>
<DIV> </DIV>
<DIV><FONT color=#800080>I'm trying to understand this statement. Rib =
profile
- OK, the shape/curve of the rib. Stress in extreme fibre - what is =
that?
Paring profile - totally lost on this one - what =
is that?</FONT></DIV>
<DIV><FONT color=#800080></FONT> </DIV>
<DIV><FONT color=#800080>Thanks.</FONT></DIV>
<DIV><FONT color=#800080></FONT> </DIV>
<DIV><FONT color=#800080>Terry Farrell</FONT></DIV></BODY></HTML>