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<DIV><FONT face="Courier New" size=2>John Hartmann =
wrote:</FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" size=2>>The points =
are:<BR><BR>>1) The only
force that gets transferred to the string is that portion of <BR>>the =
force
applied at the key that works to accelerate the hammer and
shank.<BR></FONT></DIV>
<DIV><FONT face="Courier New" size=2>Agree. But note that not =
all of the
hammer's energy is transferred to the string. </FONT><FONT =
face="Courier New"
size=2>The hammer bounces off and is still moving, so it still has =
energy, which
is </FONT><FONT face="Courier New" size=2>also wasted. But I =
think you
mean that none of the key or wippen energy makes it to </FONT><FONT
face="Courier New" size=2>the string, with which I =
agree.</FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT><BR><FONT =
face="Courier New"
size=2>>2) The portion of the force applied to the key used to =
accelerate the
<BR>>key and wippen do not go into into the string but are
wasted.</FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" size=2>Agree.<BR><BR>>3) Removing =
mass from the
key and wippen will make the action more <BR>>efficient.</FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" size=2>Hmm. Starts to get fuzzy =
here.
If you keep the same speed,</FONT><FONT face="Courier New" size=2> =
so less
energy is wasted, then I agree. </FONT><FONT face="Courier New" =
size=2>But if
you remove mass and play the key with the same force, you will have =
</FONT><FONT
face="Courier New" size=2>more speed, not the same =
speed.<BR><BR>>4) Given
our ideal action with no bending and friction losses changing =
<BR>>the hammer
mass does not effect the efficiency of the action.</FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" size=2>Same problem as 3. If you =
don't
change the mass of hammer and wippen, and </FONT><FONT face="Courier =
New"
size=2>keep the same key speed, you will waste the same amount of =
energy.
But again, </FONT><FONT face="Courier New" size=2>if you add mass to =
the hammer
and keep the same force on the key, </FONT><FONT face="Courier New" =
size=2>you
will have less acceleration, less speed, less key/wippen energy
wasted.</FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" size=2>So I guess I agree with 1 and =
2, but for 3
and 4 we need to define "efficiency" before </FONT><FONT face="Courier =
New"
size=2>we can talk about whether it stays the same or =
not.</FONT></DIV>
<DIV><FONT face="Courier New" size=2></FONT> </DIV>
<DIV><FONT face="Courier New" =
size=2>-Mark</FONT></DIV></BODY></HTML>