<HTML xmlns="http://www.w3.org/TR/REC-html40" xmlns:v == "urn:schemas-microsoft-com:vml" xmlns:o == "urn:schemas-microsoft-com:office:office" xmlns:w == "urn:schemas-microsoft-com:office:word" xmlns:st1 == "urn:schemas-microsoft-com:office:smarttags"><HEAD> <META http-equiv=Content-Type content="text/html;= charset=us-ascii"> <META content=Word.Document name=ProgId> <META content="Microsoft Word 10" name=Generator> <META content="Microsoft Word 10" name=Originator><LINK= href="cid:filelist.xml@01C4CBBB.9EE3F940"= rel=File-List><o:SmartTagType name="PersonName"= namespaceuri="urn:schemas-microsoft-com:office:smarttags"></o:Sm= artTagType> <STYLE> st1\:*{behavior:url(#default#ieooui) } </STYLE> <STYLE>  </STYLE> </HEAD> <BODY lang=EN-US style="tab-interval: .5in" vLink=blue link=blue= bgColor=white> <DIV class=Section1> That I didn't know, but I= don't measure the old center pin anyway since if your= repinning you've got a problem with that size.   I check a #21 in the birdseye= and center.  That tells what I need to know.  i.e. if= tight in both I go down a size.   If tight in the= birdseye but loose in the flange I've to go= up to #21.5 or larger or rebush.  If loose in= the birdseye, I have to go up in size.   I= think you get the idea... When repinning a section, it= becomes apparent pretty quickly what size you working= with...   David I.    ----- Original message= ----------------------------------------> From: David Love= <<A= href="mailto:davidlovepianos@comcast.net">davidlovepianos@comcas= t.net</A>> To: 'Pianotech' <<A= href="mailto:pianotech@ptg.org">pianotech@ptg.org</A>> Rec= eived: Tue, 16 Nov 2004 09:06:55 -0800 Subject: RE: Calculate= string size And, btw, for center pins, subtract 10 and divide by= 2.  <SPAN= class=GramE>Example. Center pin <SPAN= class=SpellE>mics at ..050.<SPAN= style="mso-spacerun: yes">  (50-10)/2 = #20 center= pin. = <o:p></o:p> <SPAN= style="FONT-SIZE: 10pt; COLOR: navy; FONT-FAMILY:= Arial"><o:p> </o:p> <SPAN= style="FONT-SIZE: 10pt; COLOR: navy; FONT-FAMILY: Arial">Yes,= they do ask those on the RPT exam, or at least they did.<SPAN= style="mso-spacerun: yes"> = <o:p></o:p> <SPAN= style="FONT-SIZE: 10pt; COLOR: navy; FONT-FAMILY:= Arial"><o:p> </o:p> <DIV> <SPAN= style="FONT-SIZE: 10pt; COLOR: navy; mso-no-proof: yes">David= Love <st1:PersonName>davidlovepianos@comcast.net</st1:PersonName><= FONT color=navy size=2> <o:p></o:p></DIV> -----Original Message----- <SPAN= style="FONT-WEIGHT: bold">From:= pianotech-bounces@ptg.org [mailto:pianotech-bounces@ptg.org]= On Behalf Of David= Ilvedson Sent:= Tuesday, November 16, 2004 8:21 AM <SPAN= style="FONT-WEIGHT: bold">To:= pianotech@ptg.org Subject: Re: Calculate string= size <o:p> </o:p> Guys...<o:p></o:p>  <o:p></o:p> Forget the .033,= just think of it as 33, OK?   Subtract 5 = 28, divide= by 2 = 14 wire size.<o:p></o:p>  <o:p></o:p> David= I.<o:p></o:p>  <o:p></o:p> -----= Original message= ----------------------------------------> From: Farrell= <<A= href="mailto:mfarrel2@tampabay.rr.com">mfarrel2@tampabay.rr.com<= /A>> To: Pianotech <<A= href="mailto:pianotech@ptg.org">pianotech@ptg.org</A>> Rec= eived: Tue, 16 Nov 2004 06:32:24 -0500 Subject: Re: Calculate= string size<o:p></o:p> 0.033 inches = -2.4835 wire= size?<o:p></o:p> <DIV>  <o:p></o:p></DIV> <DIV> Terry= Farrell<o:p></o:p></DIV> <BLOCKQUOTE style="BORDER-RIGHT: medium none; PADDING-RIGHT: 0in;= BORDER-TOP: medium none; PADDING-LEFT: 4pt; PADDING-BOTTOM: 0in;= MARGIN: 5pt 0in 5pt 3.75pt; BORDER-LEFT: black 1.5pt solid;= PADDING-TOP: 0in; BORDER-BOTTOM: medium none"> <DIV> -----= Original Message ----- <o:p></o:p></DIV> <DIV style="font-color: black"> From:<SPAN= style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"> <A= title=bsutton@whiteserv.com= href="mailto:bsutton@whiteserv.com">Bob Sutton</A>= <o:p></o:p></DIV> <DIV> To: <A= title=pianotech@ptg.org= href="mailto:pianotech@ptg.org">Pianotech</A>= <o:p></o:p></DIV> <DIV> Sent:= Monday, November 15, 2004 10:44= PM<o:p></o:p></DIV> <DIV> Subject: Re:= Calculate string size<o:p></o:p></DIV> <DIV> <o:p> </o:p></DIV> <DIV> Micrometer reading - 5 , and divide by= 2.    = Gw=(d-5)/2<o:p></o:p></DIV> <DIV>  <o:p></o:p></DIV> <DIV> Hope= that helps..<o:p></o:p></DIV> <DIV>  <o:p></o:p></DIV> <DIV> Bob<o:p></o:p></DIV> <BLOCKQUOTE style="BORDER-RIGHT: medium none; PADDING-RIGHT: 0in;= BORDER-TOP: medium none; PADDING-LEFT: 4pt; PADDING-BOTTOM: 0in;= MARGIN: 5pt 0in 5pt 3.75pt; BORDER-LEFT: black 1.5pt solid;= PADDING-TOP: 0in; BORDER-BOTTOM: medium none"> <DIV> -----= Original Message ----- <o:p></o:p></DIV> <DIV style="font-color: black"> From:<SPAN= style="FONT-SIZE: 10pt; FONT-FAMILY: Arial"> <A= title=mps@usol.com href="mailto:mps@usol.com">Mark= Montbriand</A> <o:p></o:p></DIV> <DIV> To: <A= title=pianotech@ptg.org= href="mailto:pianotech@ptg.org">pianotech@ptg.org</A>= <o:p></o:p></DIV> <DIV> Sent:= Monday, November 15, 2004 9:38= PM<o:p></o:p></DIV> <DIV> Subject:= Calculate string size<o:p></o:p></DIV> <DIV> <o:p> </o:p></DIV> <DIV> Greetings,<o:p></o:p></DIV> <DIV>  <o:p></o:p></DIV> <DIV> Would= someone be kind enough to tell me the formula for= calculating  the string size with the reading you get from= the= micrometer measurement?<o:p></o:p></DIV> <DIV> I.E. if= the mic tells me the thickness is .033 of an inch, What is the= string size?<o:p></o:p></DIV> <DIV>  <o:p></o:p></DIV> <DIV> Thank= you in advance<o:p></o:p></DIV> <DIV>  <o:p></o:p></DIV> <DIV> Mark<o:p></o:p></DIV> <DIV>  <o:p></o:p></DIV> <DIV> --- Outgoing mail is certified Virus= Free. Checked by AVG anti-virus system (<A= href="http://www.grisoft.com">http://www.grisoft.com</A>). Ve= rsion: 6.0.796 / Virus Database: 540 - Release Date:= 11/13/2004<o:p></o:p></DIV></BLOCKQUOTE></BLOC= KQUOTE></DIV></BODY></HTML>