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Question</title></head><body>
<div>JD wrote;</div>
<div><br></div>
<blockquote type="cite" cite>I thought from a previous posting you
were familiar with it. I'll get a gif done in the next day or
two. </blockquote>
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src="cid:a05010400b7d6b8fd53fc@[210.23.146.141].1.0"></div>
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<div>Is this the action. Thanks for sending this to the list
Clarke.</div>
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<div><br></div>
<blockquote type="cite" cite>>As long as the repetition lever
center is located in the correct position (to minimise friction - and
it isn't in the Renner/Steinway style of action), it matters little
which wood is used.<br>
<br>
<span
></span> <br>
<span
></span> J<br>
<br>
L R
C<br>
H<br>
<br>
In the Herrburger lever JL is 70, LC is 69, LR is 9.5 and R is almost
in line with LC. JC is 50. LH is 47, CH is 30. The
jack tender makes contact 26 mm from C, 4 mm above the line LC
produced.</blockquote>
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<div>John, would you mind explaining the letter diagram you have used
above, just to avoid confusion. Thanks.</div>
<div><br></div>
<blockquote type="cite" cite>>>Reduced to essentials, the action
consists of nothing but points, each of which consists of contacting
surfaces.<br>
><br>
>Sure, but in the case of the majority of contemporary actions,
little attention has been given to friction control. The
roller/knuckle contact scrubs badly since the contact is around 8 mm
below the line of centers at the rest position.<br>
</blockquote>
<blockquote type="cite" cite>Yes. The actual figure will vary
according to the rest angle of LC, but supposing it is 8, then
reducing LC to 75, as you have done, will diminish this figure and
reducing it to 69 as Herrburger did will diminish it
further</blockquote>
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<div>How?</div>
<div><br></div>
<div>Ron O</div>
<div>-- <br>
______________________________<br>
<br>
Website: http://www.overspianos.com.au<br>
Email:
mailto:ron@overspianos.com.au<br>
______________________________</div>
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