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<DIV><FONT color=#000000 size=2>Yes, your logic right, but the =
formula I would
use would be F = ma. Brian</FONT></DIV>
<BLOCKQUOTE
style="BORDER-LEFT: #000000 solid 2px; MARGIN-LEFT: 5px; PADDING-LEFT: =
5px">
<DIV><FONT face=Arial size=2><B>-----Original =
Message-----</B><BR><B>From:
</B>Brian Trout <<A
=
href="mailto:btrout@desupernet.net">btrout@desupernet.net</A>><BR><B=
>To:
</B><A href="mailto:pianotech@ptg.org">pianotech@ptg.org</A> =
<<A
=
href="mailto:pianotech@ptg.org">pianotech@ptg.org</A>><BR><B>Date:
</B>Monday, 29 November 1999 12:32<BR><B>Subject: </B>Re: String =
breakage in
relation to hammer mass<BR><BR></DIV></FONT>
<DIV><FONT size=2>Hi Brian,</FONT></DIV>
<DIV> </DIV>
<DIV><FONT size=2>Not to be obnoxious here, but perhaps the =
formula may have
some relevance.</FONT></DIV>
<DIV> </DIV>
<DIV><FONT size=2>Although we're not dealing with parameters of =
light speed,
the formula does give a very basic premise that will apply to much =
of the
physical world.</FONT></DIV>
<DIV> </DIV>
<DIV><FONT size=2>In this formula, it is demonstrated that an =
increase in
mass will also bring about an increase in energy if the formula is =
to remain
valid. Any change on one side of the "=" sign =
would also
need to be reflected on the other side of the "=" sign =
to maintain
the ratio implied. ... Just thinkin' in =
cyberspace...</FONT></DIV>
<DIV> </DIV>
<DIV><FONT size=2>Hope you're having a nice weekend. It's =
been a busy
one here.</FONT></DIV>
<DIV> </DIV>
<DIV><FONT size=2>Best wishes, </FONT></DIV>
<DIV> </DIV>
<DIV><FONT size=2>Brian Trout</FONT></DIV>
<DIV><FONT size=2>Quarryville, PA</FONT></DIV>
<DIV><FONT size=2><A
=
href="mailto:btrout@desupernet.net">btrout@desupernet.net</A></FONT></D=
IV>
<DIV> </DIV>
<BLOCKQUOTE
style="BORDER-LEFT: #000000 solid 2px; MARGIN-LEFT: 5px; =
MARGIN-RIGHT: 0px; PADDING-LEFT: 5px; PADDING-RIGHT: 0px">
<DIV style="FONT: 10pt arial">----- Original Message ----- =
</DIV>
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: =
black"><B>From:</B>
<A href="mailto:bholden@wave.co.nz" =
title=bholden@wave.co.nz>Brian
Holden</A> </DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A
href="mailto:pianotech@ptg.org"
title=pianotech@ptg.org>pianotech@ptg.org</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Sunday, November =
28, 1999
2:32 PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: String =
breakage in
relation to hammer mass</DIV>
<DIV><BR></DIV>
<DIV><FONT color=#000000 size=2>PS, Jim's formula: E =
= mc2
(energy = mass x speed of light2) would have little to do with =
the
breaking string problem methinks - BH. </FONT></DIV>
<BLOCKQUOTE
style="BORDER-LEFT: #000000 solid 2px; MARGIN-LEFT: 5px; =
PADDING-LEFT: 5px">
<DIV><FONT face=Arial size=2><B>-----Original
Message-----</B><BR><B>From: </B>M J & L V Ashby <<A
=
href="mailto:mjashby@xtra.co.nz">mjashby@xtra.co.nz</A>><BR><B>To:
</B>Piano List <<A
=
href="mailto:pianotech@ptg.org">pianotech@ptg.org</A>><BR><B>Date:
</B>Sunday, 28 November 1999 21:32<BR><B>Subject: </B>String =
breakage in relation to hammer mass<BR><BR></DIV></FONT>
<DIV><FONT color=#000000 size=2>If a hammer is unusually =
heavy will
it contribute to string breakage?</FONT></DIV>
<DIV> </DIV>
<DIV><FONT size=2>Michael
</FONT></DIV></BLOCKQUOTE></BLOCKQUOTE></BLOCKQUOTE></BODY></HTML>