Hexagonal Hammer Shank

Ron Nossaman RNossaman@cox.net
Tue, 18 Nov 2003 15:42:00 -0600


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>Ron,
>
>The moment of inertia has nothing to do with stiffness.  It has to do with
>where the mass is.  The inertia of the shank is a tiny fraction of the
>total inertia of the shank and hammer system.  The hammer head is where the
>big moment of inertia is.  The stiffness of the shank is important so that
>the hammer head does not wiggle and wobble.  At the same time, a heavy
>shank would put mass where we don't want it, but even in the shank, it
>depends upon where the mass is.

Jim.
This is the moment of inertia calculation that is a part of all of the 
various flexure formulae used to calculate beam deflection under static load.

In inches and pounds: Deflection of center loaded 
beam=(weight*length^3)/(48*E*I)
where E is the modulus of elasticity, and I the moment of inertia 
determined by the shape and cross sectional dimensions.

>If we are interested in stiffness, I think the best thing to do is to
>measure it.  That's what I plan to do, when I get time.  There are just too
>many variables in a stick of wood to try to calculate it.
>
>Jim Ellis

If all that's desired is a relative stiffness of different cross sectional 
profiles made from the same material, the variation in wood is the best 
justification I know for calculation, because calculation removes that 
variation. I was just trying to supply a quick shorthand indicator of that 
relative stiffness.

Ron N

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