> >> So what quantity do we have that is mass times velocity.... but is > clearly differentiates between each equal product... > > Well, mass times velocity is *momentum.* > > >> Clearly... 2 x 2 does not equal 4 x 1..... at least in the case of how > much mass at what speed hits any given other mass. > >> What quantity am I looking for here ? > > I'm not sure what you mean here. Kinetic energy, (mv^2)/2, perhaps > differentiates, sort of, I guess, if I understand you correctly. Only you'd > be looking at 2 x 2^2 / 2 being different from 4 * 1^2 / 2, etc. Is that > what you mean? > >RicB wrote: > >What I am saying is that a 10 pound ball going at 5 m/s is going to have a >completly different affect then a 5 pound ball going at 10 m/s tho both have a >momentum of 50 momentum units. I see what you're saying, and the only thing I come up with is the kinetic energies are different (unless V=sqrt(2)). (Another) Example When M=1, V=4, M*V=4 but energy = 8 When M=2, V=2, M*V=4 but energy = 4 So I guess to capture this you really have to use momentum AND energy, or mass AND velocity. You're right, momentum by itself doesn't capture this. (You didn't really mix pounds with m/s up there did you? That's almost as bad as my 1.75"/10mm blow/dip ratio! :) ) -Mark
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