---------------------- multipart/alternative attachment In a message dated 11/1/03 12:53:13 AM, RNossaman@cox.net writes: > No, it won't. It will be curved more in the middle and less at the ends. I > used two straight edges. Starting with a line representing the anticipated > maximum length of a rib of that particular radius, I computed the height of > the arc segment represented by that chord at that radius. Then I drove pins > in the points at the ends of the chord, and the center of the arc segment > at the computed height above the chord. Placing the two straight edges one > each on the pins at the ends of the chord, and overlapping above, but both > touching, the pin in the center, I tacked them together. Placing a pencil > in the shallow V produced at the intersection of the straightedges, I slid > the straightedge assembly on the three pins so that the pencil went from > one end of the chord to the other - describing the arc segment. > > Realistically, the exact shape of the described arc isn't anything like > critical to the ultimate performance of the assembly. The chosen radii and > rib dimensions, balanced against the anticipated bearing load and resulting > deflection are significantly more important. > believe this two straightedges method is shown in fine woodworking magazine, and the formula for rise of segment/arc of a circle is in machinery's handbook. I am not strong on math but I presumed I had solved correctly when I did Wolfenden's suggested radius and it came out exactly .625 or 5/8 inch. My question is: why express these rises of arc in such an arcane fashion as radius of a HUGE circle? Is it because of the need to be uniform despite the length of arc required ? Glenn C. ---------------------- multipart/alternative attachment An HTML attachment was scrubbed... URL: https://www.moypiano.com/ptg/pianotech.php/attachments/0d/cd/02/03/attachment.htm ---------------------- multipart/alternative attachment--
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