Doppler puzzle

[Amy Zilk]

Dude!  What Doppler equation are you using?  Both the original sent 
frequency and the observed frequency are in the equation.  Manipulate 
the algebra to get the ratio, and the dimensions drop out.

az


John Delmore wrote:
>
>  
>
> No dice, Amy, you can't use this dimensionless ratio in the Doppler 
> equation.  You have to have a frequency.  It DOESN'T matter what pitch 
> (frequency) you measure.  The problem comes when you try to use a 
> logarithmic scale (cents) in a linear equation (Hz in Doppler).
>
> JD
>
> ------------------------------------------------------------------------
>
> *From:* pianotech-bounces at ptg.org [mailto:pianotech-bounces at ptg.org] 
> *On Behalf Of *Amy Zilk
> *Sent:* Wednesday, June 21, 2006 5:46 PM
> *To:* Pianotech List
> *Subject:* Re: Doppler puzzle
>
>  
>
> Try dividing any two frequencies that differ by 10 cents.  It's a 
> constant.  Ten cents difference anywhere in the spectrum is a constant 
> frequency ratio of ~1.0579.  The doppler shift is found in terms of 
> this ratio and you can convert the 10 cents difference into the ratio 
> of frequencies.  It's counterintuitive for me (but not for Mark), that 
> it doesn't matter which pitch you are measuring but that's the way it 
> works.
> az
>
>
>
>
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