Hi Keith
Yes.... well I see where we are getting mixed up with each other here.
I has seemed to me that you were saying that the lever was indeed a
simple 3rd class lever with the input arm being the whippen cushion to
the whippen flange center and the output arm the whippen flange center
to the jack center. I think I said in my last reply that this
perspective requires either a very large move to create a significant
change in ratio or the perspective was wrong and you had to figure in
another component which made the whole situation a bit more
complicated. I dont see that you've explained this other component.
Grin... given your example I'm not even sure at this point you accept
the whippen is a 3rd class lever to begin with. Besides... you throw in
a post (which I suppose is supposed to represent the jack itself) and
dont take into consideration that the angle this post takes is supposed
to change depending on the placement of the input and output loads.
Please do not misunderstand... I mean no disrespect. I am very sure the
picture you are drawing with your words is very clear in your mind...
but why dont you just use a simple drawing using MS Paint or something
like that to illustrate what you are saying.
Strikes me that it makes no real difference whether you figure the
whippen as 3rd class lever using the flange center to the jack top or
the flange center to the jack center in this context. Either way moving
the whole whippen 2 mm moves both points 2 mm. Reseting the jack angle
to meet the knuckle in the case you view the later creates essentially
the same effect as if you simply took the view of the former. Which may
explain why most folks simply decide to figure the output arm from the
jack top. Nothing imaginary about this at all me thinks.
Draw a pic and let me get a clearer look at what you are getting at :)
Cheers
RicB
Excuse me, you are not accepting the fact that the resistance lever
arm is
to the jack center pin. This by definition of a lever. Show me the solid
beam that translates the force from the capstan directly to the top
of the
jack. You have an imaginary RA. The force is transmitted through the
lever
arms to the jack center pin. The center pin then lifts the jack. If
I change
the EA of the wippen, the force at the jack center pin will change.
Am I not
correct on this? The premise you base everything on is that the RA
changes
with the rail move. It does not so a 2mm move is a lot and the input at
center pin to the jack, even though it changes slightly with the
rotation of
the jack, is counter acted by the change in the alignment at the top
of the
jack. Therefore all of the resultant changes MUST be due to the
change in
the EA of the wippen.
Picture this. A five story building. You have a motor that lifts a
whole
bunch of weight 3" and lets it back down. You need work done on all the
floors. You put the motor in the basement and stand a post up
through the 5
stories. On the 5th story you have machine that is the most
important and
needs to accelerate a part from the floor to the ceiling and you
need more
lift of the post to make it work. So you put in a 2nd class lever in the
basement between the motor and the post. Now this post does this
same work
on every floor. Do I measure the RA of the lever in the basement to 5th
floor, the 4th floor, the 1st floor? If I disconnect the equipment
on the
5th floor and move it to the 2nd, do I have to recalculate the RA
and adjust
the setup so the same work is then accomplished?
Keith Roberts
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