Hi Keith Yes.... well I see where we are getting mixed up with each other here. I has seemed to me that you were saying that the lever was indeed a simple 3rd class lever with the input arm being the whippen cushion to the whippen flange center and the output arm the whippen flange center to the jack center. I think I said in my last reply that this perspective requires either a very large move to create a significant change in ratio or the perspective was wrong and you had to figure in another component which made the whole situation a bit more complicated. I dont see that you've explained this other component. Grin... given your example I'm not even sure at this point you accept the whippen is a 3rd class lever to begin with. Besides... you throw in a post (which I suppose is supposed to represent the jack itself) and dont take into consideration that the angle this post takes is supposed to change depending on the placement of the input and output loads. Please do not misunderstand... I mean no disrespect. I am very sure the picture you are drawing with your words is very clear in your mind... but why dont you just use a simple drawing using MS Paint or something like that to illustrate what you are saying. Strikes me that it makes no real difference whether you figure the whippen as 3rd class lever using the flange center to the jack top or the flange center to the jack center in this context. Either way moving the whole whippen 2 mm moves both points 2 mm. Reseting the jack angle to meet the knuckle in the case you view the later creates essentially the same effect as if you simply took the view of the former. Which may explain why most folks simply decide to figure the output arm from the jack top. Nothing imaginary about this at all me thinks. Draw a pic and let me get a clearer look at what you are getting at :) Cheers RicB Excuse me, you are not accepting the fact that the resistance lever arm is to the jack center pin. This by definition of a lever. Show me the solid beam that translates the force from the capstan directly to the top of the jack. You have an imaginary RA. The force is transmitted through the lever arms to the jack center pin. The center pin then lifts the jack. If I change the EA of the wippen, the force at the jack center pin will change. Am I not correct on this? The premise you base everything on is that the RA changes with the rail move. It does not so a 2mm move is a lot and the input at center pin to the jack, even though it changes slightly with the rotation of the jack, is counter acted by the change in the alignment at the top of the jack. Therefore all of the resultant changes MUST be due to the change in the EA of the wippen. Picture this. A five story building. You have a motor that lifts a whole bunch of weight 3" and lets it back down. You need work done on all the floors. You put the motor in the basement and stand a post up through the 5 stories. On the 5th story you have machine that is the most important and needs to accelerate a part from the floor to the ceiling and you need more lift of the post to make it work. So you put in a 2nd class lever in the basement between the motor and the post. Now this post does this same work on every floor. Do I measure the RA of the lever in the basement to 5th floor, the 4th floor, the 1st floor? If I disconnect the equipment on the 5th floor and move it to the 2nd, do I have to recalculate the RA and adjust the setup so the same work is then accomplished? Keith Roberts
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