OK here goes: Let X = years to go to meet requirement Let A = age when requirements are met Solve for age A when number of years of experience equal 1/2 of age. Given: Current age of 54 and experience of 22 ( 54-22=32 or age starting experience.) (X+32)+(X+22)=54+X (years to go to meet requirement) X+22=(54+X)/2 2X+44=54+X X+44=54 X=10 A=54+X A=64!!!!!!!!!!!!!! (almost time to retire) (And I did all this AFTER tuning 8 pianos and installing a set of castors) You people just ask too much of me:-) Oh, Diane - Happy Birthday! John R. Fortiner Billings, MT. On Wed, 03 May 2000 22:01:56 +0200 Richard Brekne <richardb@c2i.net> writes: > Ditto !! Hope you had a nice one.. > > ok you math genuises... grin... how many years before > Diane will have spent half her life as a technician ??? > Can any of you's write out an algebraic solution ? > > JIMRPT@AOL.COM wrote: > > > In a message dated 5/03/2000 1:56:26 AM, you wrote: > > > > <<54.0 today, 22 years tech. > > Diane Hofstetter>> > > > > HAPPY BIRTHDAY DIANE!!!!!! > > Jim Bryant (FL) > > -- > Richard Brekne > Associate PTG, N.P.T.F. > Bergen, Norway > > > > ________________________________________________________________ YOU'RE PAYING TOO MUCH FOR THE INTERNET! Juno now offers FREE Internet Access! Try it today - there's no risk! For your FREE software, visit: http://dl.www.juno.com/get/tagj.
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