This is a multi-part message in MIME format. ---------------------- multipart/alternative attachment Hi all, Thanks for the advice about techniques to even out the SW curve! That = should give me a variety of techniques to use/combine in order to even = out the jags. But the question is one of what my target curve should *really* be. = Hmmmm.... My thoughts: The unmodified SW curve is obviously very linear. (Yes, I know what = linear means. I "minored" in mathematics, sort of -- except that my U. = didn't officially recognize minors). Stanwood's curves, OTOH, are all = concave downwards. I was advised off list that I shouldn't force the hammers to = artificially conform to a standardized Stanwood curve but to simply even = out the jags to make the action smooth from bottom to top. There's = something to be said for this idea. But as I got to thinking about the SW curves, I was wondering, where do = they REALLY come from? That is, where does the shape come from? I = suspect the hammer manufacturing people might be able to enlighten me as = to this. (Ray???) I'm *guessing* that the felt is denser than the = molding, and when the hammer becomes skinnier, it loses more felt than = molding, resulting in a more precipitous dropoff in weight at the higher = end. This would occur with a constant hammer length and a linear = variation in hammer and molding (and felt) width. Am I anywhere close = on this idea??? Contrast this function with other functions that might actually relate = to optimal hammer mass: String length and mass both decrease with the = note number, with a function that is concave upwards. Note frequency = increases with a function that is concave upwards. Note period (inverse = of frequency) increases with a function that is concave upwards. The = Stanwood curve seems rather meaningless with regard to any of these = functions. For instance, it might be good to match hammer mass to = string mass by some proportion. Right? As the scale goes up, string = length and mass approach an asymptote of zero. Therefore, shouldn't = hammer mass approach an asymptote of zero? Instead, the curve starts = taking a dive in the treble. If the scale went up well past 88, hammer = mass would eventually crash to zero. Because these curves do not have = the same form, the relationship between hammer and string mass is = anything but constant. That doesn't make sense. So is this something that is the way it is just because of tradition -- = because the cauls are built that way, and that's what ya' get? =20 Now that I look at my linear SW curve (with jags), I'm wondering if this = isn't REALLY a closer match to something meaningful (like string mass) = than the idealized Stanwood curves. Any thoughts, y'all? Peace, Sarah ---------------------- multipart/alternative attachment An HTML attachment was scrubbed... URL: https://www.moypiano.com/ptg/pianotech.php/attachments/94/78/1c/f1/attachment.htm ---------------------- multipart/alternative attachment--
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