Issac As I understand it.. the "moment of inertia" for the hammer and shank assembly is determined by the amount of mass, and its position from the centerpin. The knuckle doesnt have anything to do with this outside of being a tiny amount of mass itself... and only then if you physically move its glued position on the shank.. and the resulting change in moment of inertia would be like null for all practical purposes. If this is in error... then Don, or somebody else please chime in. More importantly tho.. such a move will change the leverage of the hammer shank... which seems to be what you are refering to. Isaac sur Noos wrote: > > I was taking in account the change in roller position, that is what I > called higher moment of inertia on the hammer (lighter heads but > roller near to the center pin vs. actual 17 mm setup) while I don't > have the maths for , for instance differences of weight in the hammer > vs. different placement of the roller relation. > Cheers RicB -- Richard Brekne RPT, N.P.T.F. UiB, Bergen, Norway mailto:rbrekne@broadpark.no http://home.broadpark.no/~rbrekne/ricmain.html http://www.hf.uib.no/grieg/personer/cv_RB.html
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